Discuss




(apparently QZ has disabled ASCII greek letters)

easy proof of this identity:

let A be the adjacent side of the right angle triangle
and O be the opposite side of the right angle triangle
and H be the hypotenuse (no you are a hypotenuse).
Then sin (a) = O/H and cos(a) = (A/H)
sin^2(a) + cos^2(a) = O^2/H^2 + A^2/H^2 = (O^2 + A^2)/H^2
O^2 + A^2 = H^2 by pythagoras and martian law
so (O^2+A^2)/H^2 = H^2/H^2 = 1.

LARRRRS!

this only proves the identity for a being a real number :P

a = 2 π n + π, n ϵ Z

greek letters work fine for me off char map

I don't understand any of this.

qz better not had deactivated my nickname!

yer history !

does the look of disapproval live on?

[quote poster=ಠ_ಠ; 31625; 570589]does the look of disapproval live on? [/quote]

HE DOOOOOOOOOOOOOOOOOOO

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pimpin'

love the hat